By Rchard Brry

ISBN-10: 0684184761

ISBN-13: 9780684184760

**Read Online or Download Build your own Telescope (1985)(en)(276s) PDF**

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**Extra resources for Build your own Telescope (1985)(en)(276s)**

**Sample text**

Thus the inward (negative) magnetic flux must be exactly balanced by the outward (positive) magnetic flux. Since many of the symbols in Gauss’s law for magnetic fields are the same as those covered in the previous chapter, in this chapter you’ll find only those symbols peculiar to this law. Here’s an expanded view: Reminder that the magnetic field is a vector Reminder that this integral is over a closed surface Dot product tells you to find the part of B parallel to nˆ (perpendicular to the surface) ∫B S The unit vector normal to the surface nˆ da = 0 The magnetic field in Teslas An increment of surface area in m2 Reminder that this is a surface integral (not a volume or a line integral) Tells you to sum up the contributions from each portion of the surface Gauss’s law for magnetic fields arises directly from the lack of isolated magnetic poles (‘‘magnetic monopoles’’) in nature.

This expression is positive for 0 < x < 12, 0 at x ¼ 12, and negative for 12 < x < 32, just as your visual inspection suggested. 13(b), which represents a slice through a spherically symmetric vector field with amplitude increasing as the square of the distance from the origin. Thus ~ A ¼ r 2^r . 13(b) is increasing linearly with distance from the origin. 13(c), which is similar to the previous case but with the amplitude of the vector field decreasing as the square of the distance from the origin.

After all, while the electric field does appear in the equation, it is only the normal component that emerges from the dot product, and it is only the integral of that normal component over the entire surface that is proportional to the enclosed charge. Do realistic situations exist in which it is possible to dig the electric field out of its interior position in Gauss’s law? Happily, the answer is yes; you may indeed find the electric field using Gauss’s law, albeit only in situations characterized by high symmetry.

### Build your own Telescope (1985)(en)(276s) by Rchard Brry

by Ronald

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